2024届金学导航答案网

(cos3r+sn3)十(ms241r+sn241cos45+o90r-411号99.解析：由条件得√2sina=sinB①，-cosa=√3cosB②，3X①2+②，得6sina+cos2a=3因为e为第二象限加，所以sna==2sn&5110.解...

件B,则n)=4E=60.A而B:“乙站在甲右侧，且甲丙相邻”，n(B)生=24，所以An(AB)=n(A)-n(AB)=36故选C8.C解：由ON=c可得FN⊥FN。设|N=t,则|F,N=t+2a,所以(t+2a)2+t2=4c2→...

第5期B1版Keys:(One possible version)词汇过关[单词汉译英]1.theater2.seat3.screen4.ticket5.song6.reporter7.service8.menu9.talent10.magician11.winner12.p...

第5期B1版Keys:(One possible version)词汇过关[单词汉译英]1.theater2.seat3.screen4.ticket5.song6.reporter7.service8.menu9.talent10.magician11.winner12.p...